Lim Academic Calendar
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
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Society of Asian Scientists and Engineers Chung, Lucia
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
My Doctor Online Claudine Yee
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
Su Hsien Lim > Specialists > Yale Medicine
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
Dr. Jeanne Y. Oh, MD Aurora, CO Pediatrics
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.