Lim College Academic Calendar
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
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Anne CC Lee, Community Partner for Data Drives Change A Pilot Study to
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
Dr. Jeanne Y. Oh, MD Aurora, CO Pediatrics
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
The President's Stevens Institute of Technology
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.
Johanna C. Los Angeles County, California, United States
具体回答如下: (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) 因为x→∞ 所以1\x→0 用等价无穷小代换ln (1+1/x) =1\x 原式:当 (x→∞) lim (1+1/x)^x=lime^xln (1+1/x) =lime^x*1/x=e 极限的性质: 和.